An equilibrium is established in which both the forward (fwd) and the reverse (rev) reactions are elementary. If the equilibrium constant K_c = 1.6 *10¯² and the rate constant k_fwd = 8.0 * 10¯⁷ s¯¹ what is the value of k_rev?

Question

Quizplus · Accepted Answer

The equilibrium constant Kc is the ratio of the rate constants of the forward and reverse reactions: Kc = kfwd / krev. Solving for krev gives krev = kfwd / Kc = (8.0 * 10¯⁷ s¯¹) / (1.6 * 10¯²) = 5.0 * 10¯⁵ s¯¹.

An Equilibrium Is Established in Which Both the Forward (Fwd)