The rate law for the reaction 3A $\rightarrow$ C is Rate = 4.36 *10¯² L mol¯¹ hr¯¹[A]² What is the half-life for the reaction if the initial concentration of A is 0.250 M?

Question

Quizplus · Accepted Answer

The reaction is second-order, and the half-life for a second-order reaction is given by $ t_{1/2} = \frac{1}{k[A]_0} $. Substituting the given values: $ t_{1/2} = \frac{1}{4.36 \times 10^{-2} \times 0.250} \approx 91.7 $ hr.

The Rate Law for the Reaction 3A →\rightarrow→ C Is Rate = 4

The Rate Law for the Reaction 3A $\rightarrow$ C Is Rate = 4