Predict the ideal bond angles around nitrogen in N₂F₂ using the molecular shape given by the VSEPR theory. (The two N atoms are the central atoms.)

Question

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In N₂F₂, the nitrogen atoms are each surrounded by four electron pairs, three of which are bonding and one of which is a lone pair. According to VSEPR theory, this results in a trigonal pyramidal molecular shape, where the ideal bond angle is 120°. Therefore, the ideal bond angles around nitrogen in N₂F₂ is 120°.

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Predict the Ideal Bond Angles Around Nitrogen in N₂F₂ Using $\degree$