For the normal approximation to the binomial distribution with n = 100 and p = ½ , a score of X = 60 corresponds to a z-score of z = 2.00.

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Quizplus · Accepted Answer

The z-score is calculated as (X - np) / sqrt(np(1-p)), where X is the score, n is the number of trials, and p is the probability of success. In this case, X = 60, n = 100, and p = ½, so the z-score is (60 - 100*½) / sqrt(100*½*(1-½)) = 2.00.

For the Normal Approximation to the Binomial Distribution with N