For the population of scores shown in the frequency distribution table, the mean is ____.
$\begin{array}{cc}
X & f \
\hline 5 & 2 \
4 & 1 \
3 & 3 \
2 & 2 \
1 & 2
\end{array}$

A) $ 15 / 5=3 $
B) $ 15 / 10=1.50 $
C) $ 29 / 5=5.80 $
D) $ 29 / 10=2.90 $

Question

For the population of scores shown in the frequency distribution table, the mean is ____. 
$\begin{array}{cc}
X & f \
\hline 5 & 2 \
4 & 1 \
3 & 3 \
2 & 2 \
1 & 2
\end{array}$

A) $ 15 / 5=3 $
B) $ 15 / 10=1.50 $
C) $ 29 / 5=5.80 $
D) $ 29 / 10=2.90 $

Quizplus · Accepted Answer

The mean is calculated by dividing the sum of all scores by the total number of scores. The sum of scores is $ (5*2) + (4*1) + (3*3) + (2*2) + (1*2) = 29 $. The total number of scores is $ 2 + 1 + 3 + 2 + 2 = 10 $. Therefore, the mean is $ 29 / 10 = 2.90 $.

For the Population of Scores Shown in the Frequency Distribution Xf5241332212\begin{array}{cc}X & f \\\hline 5 & 2 \\4 & 1 \\3 & 3 \\2 & 2 \\1 & 2\end{array}X54321​f21322​​

For the Population of Scores Shown in the Frequency Distribution $\begin{array}{cc}X & f \\\hline 5 & 2 \\4 & 1 \\3 & 3 \\2 & 2 \\1 & 2\end{array}$