What is the value of µ for the normal approximation to the binomial distribution with n = 72 and p = 1/3?
A)12
B)24
C)36
D)48

Question

What is the value of µ for the normal approximation to the binomial distribution with n = 72 and p = 1/3?​
A)​12
B)​24
C)​36
D)​48

Quizplus · Accepted Answer

For a binomial distribution with n trials and probability of success p, the mean (µ) is given by µ = np. 
Substituting n=72 and p=1/3, we get µ = 72*(1/3) = 24. 
Therefore, the normal approximation to this binomial distribution will have a mean of 24. Choice B is the correct answer.

What Is the Value of µ for the Normal Approximation