What is the standard deviation for the normal approximation to the binomial distribution with n = 72 and p = 1/3?
A)4
B)6
C)16
D)24

Question

What is the standard deviation for the normal approximation to the binomial distribution with n = 72 and p = 1/3?​
A)​4
B)​6
C)​16
D)​24

Quizplus · Accepted Answer

The standard deviation for the normal approximation to the binomial distribution is calculated using the formula $\sigma = \sqrt{n \cdot p \cdot (1-p)}$, where $n$ is the number of trials and $p$ is the probability of success on each trial. Substituting $n = 72$ and $p = 1/3$ into the formula gives $\sigma = \sqrt{72 \cdot (1/3) \cdot (2/3)} = \sqrt{48} = 4$.

What Is the Standard Deviation for the Normal Approximation to the Binomial