What is the kinetic energy of the photoelectrons emitted from a sodium surface ($\varPhi$ = 2.9 * 10^-19 J) when it is irradiated by photons with a wavelength of 350 nm?

Question

Quizplus · Accepted Answer

The kinetic energy of the photoelectrons can be calculated using the photoelectric equation: $KE = hf - \phi$, where $KE$ is the kinetic energy, $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{Js}$), $f$ is the frequency of the incident light, and $\phi$ is the work function of the material. The frequency $f$ can be found from the wavelength $\lambda$ using the relation $f = \frac{c}{\lambda}$, where $c$ is the speed of light ($3.00 \times 10^8 \, \text{m/s}$). Given the wavelength $\lambda = 350 \, \text{nm} = 350 \times 10^{-9} \, \text{m}$, and the work function $\phi = 2.9 \times 10^{-19} \, \text{J}$, we can calculate the kinetic energy of the photoelectrons. The correct calculation leads to a kinetic energy value that matches the option provided in D.

What Is the Kinetic Energy of the Photoelectrons Emitted from a Sodium