Light intensity (I) can be described as the power emitted by a light source (P) over a given area in meters squared) .Suppose a 100 W mercury vapor lamp emits 365.4 nm photons equally in all directions.At a distance of 1.450 m, how many photons hit per square meter per second?
(1 W = 1 J/s; I = P/Area = P/4 d 2 , where d is the distance.)
A) 5 * 107 photons
B) 7 * 109 photons
C) 9 * 1016 photons
D) 7 * 1018 photons
E) 6 * 1019 photons
Correct Answer:
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