What is the ground-state electron configuration of an Al³⁺ion?

Question

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The given ion is $Al^{3+}$, which means it has lost three electrons from its neutral state. The neutral aluminum atom has an electron configuration of $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{1}$. Losing three electrons, particularly the $3s^{2} 3p^{1}$ electrons, leaves it with $1s^{2} 2s^{2} 2p^{6}$, which is the electron configuration of neon, a noble gas. This configuration represents a filled valence shell, making it the ground-state electron configuration for $Al^{3+}$.

What Is the Ground-State Electron Configuration of an Al3+ion? A) 1s22s22p63s23p1 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1} 1s22s22p63s23p1

What Is the Ground-State Electron Configuration of an Al³⁺ion?
A) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}$