Copper(II) sulfate (CuSO₄) can be used to control algae growth.Aqueous CuSO₄ solutions that come in contact with the surface of galvanized (zinc-plated) steel pails undergo the following reaction:
CuSO₄ (aq) +Zn(s) $\rightarrow$ Cu(s) +ZnSO₄ (aq)
How many grams of zinc would react with 454 g (1 lb) of CuSO₄ (159.61 g/mol) ?

Question

Copper(II) sulfate (CuSO₄) can be used to control algae growth.Aqueous CuSO₄ solutions that come in contact with the surface of galvanized (zinc-plated) steel pails undergo the following reaction:
CuSO₄ (aq) +Zn(s)

\rightarrow

Cu(s) +ZnSO₄ (aq)
How many grams of zinc would react with 454 g (1 lb) of CuSO₄ (159.61 g/mol) ?

Quizplus · Accepted Answer

First, calculate the moles of CuSO4 (CuSO₄) using its molar mass: 454 g / 159.61 g/mol = 2.845 moles. The reaction between CuSO4 and Zn is 1:1, so 2.845 moles of Zn will also react. The molar mass of Zn is approximately 65.38 g/mol, so the mass of Zn that will react is 2.845 moles * 65.38 g/mol = 186 g.

Copper(II) Sulfate (CuSO4) Can Be Used to Control Algae Growth →\rightarrow→

Copper(II) Sulfate (CuSO₄) Can Be Used to Control Algae Growth $\rightarrow$