If 980 G B₂O₃ (69 $\rightarrow$ 2 BF3 (G) +3 H₂ O(l)
A)72

If 98.0 g B₂O₃ (69.62 g/mol) and 125 g HF (20.01 g/mol) are combined and allowed to react according to the given equation, what mass of the excess reactant will be left over?
B₂ O₃ (s) +6 HF(aq) $\rightarrow$ 2 BF3 (g) +3 H₂ O(l)

A) 72.5 g B₂O₃ will be left over.
B) 25.5 g B₂O₃ will be left over.
C) 28.2 g HF will be left over.
D) 7.34 g HF will be left over.
E) Both are completely consumed.