How many grams of glucose (C6H12O6, 180.16 g/mol) would be required to prepare 2.50 L of a 0.278 M glucose solution that could be used in an IV bag?
A) 6.95* 102g
B) 1.11 * 102g
C) 5.01 * 101g
D) 4.50 * 102g
E) 1.25 * 102g
Correct Answer:
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