Which of the following represents the maximum mercury levels in drinking water, which is approximately 2 ppb? Assume the density of drinking water is 1 g/mL.

Question

Quizplus · Accepted Answer

To find the concentration of mercury in drinking water in nM (nanomolar), we first convert 2 ppb (parts per billion) to a concentration in molarity (M). 1 ppb of a substance is equivalent to 1 μg/L. Therefore, 2 ppb is 2 μg/L. The molar mass of mercury (Hg) is approximately 200.59 g/mol. Thus, the concentration in molarity is calculated as follows: (2 μg/L) / (200.59 g/mol) = 2 x 10^-3 mg/L / 200.59 g/mol = 1 x 10^-5 M = 10^-2 mM = 10 nM.

Which of the Following Represents the Maximum Mercury Levels in Drinking