When the oxidation-reduction reaction shown here is balanced using the smallest whole-number coefficients, how many electrons are transferred? Sn(s) +CL₂(g) $\rightarrow$ SnCL₄ (s)

Question

Quizplus · Accepted Answer

In the given reaction, tin (Sn) is oxidized to tin(IV) chloride (SnCl4), and chlorine (Cl2) is reduced. The balanced half-reactions are:Oxidation: Sn → Sn^4+ + 4e^-Reduction: Cl2 + 4e^- → 2Cl^-Thus, 4 electrons are transferred in the process.

When the Oxidation-Reduction Reaction Shown Here Is Balanced Using the Smallest