A 500 mg dietary supplement of L-lysine (an amino acid, 146.99 g/mol) required 68.4 mL of 0.100 M NaOH to reach the end point.How many hydrogen ions were removed for each L-lysine molecule in this titration?

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Quizplus · Accepted Answer

The moles of NaOH used are 0.00684 mol (68.4 mL * 0.100 M). The moles of L-lysine are 0.0034 mol (500 mg / 146.99 g/mol). The ratio of NaOH to L-lysine is 2:1, indicating that 2 hydrogen ions are removed per L-lysine molecule.

A 500 Mg Dietary Supplement of L-Lysine (An Amino Acid