What will be the final temperature of a 10.0 g piece of iron [c_p = 0.45 J/(g .$\degree$C)], initially at 25$\degree$C, if it is supplied with 9.5 J from a stove?

Question

Quizplus · Accepted Answer

The final temperature can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat supplied (9.5 J), $m$ is the mass of the iron (10.0 g), $c$ is the specific heat capacity of iron (0.45 J/g°C), and $\Delta T$ is the change in temperature. Rearranging the formula to solve for $\Delta T$, we get $\Delta T = \frac{q}{mc}$. Plugging in the values, $\Delta T = \frac{9.5}{10.0 \times 0.45} = 2.11°C$. Adding this change to the initial temperature of 25°C gives a final temperature of approximately 27°C.

What Will Be the Final Temperature of a 10 °\degree° C)], Initially at 25

What Will Be the Final Temperature of a 10 $\degree$ C)], Initially at 25