The dissolution of cesium hydroxide in water is exothermic ($\Delta$H_soln = -71.55 kJ/mol).Calculate the change in temperature of a solution produced by dissolving 0.150 kg CsOH (150 g/mol) in 1.00 kg water.Assume the heat capacity of the solution is 4.18 J/(g . $\degree$C).

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The heat released is calculated using the formula q = n * ΔH, where n is the number of moles of CsOH. The moles of CsOH = 0.150 kg / 150 g/mol = 1 mol. Thus, q = 1 mol * (-71.55 kJ/mol) = -71.55 kJ = -71550 J. The temperature change is ΔT = q / (mass * specific heat capacity) = -71550 J / (1150 g * 4.18 J/g°C) = 14.9°C.

The Dissolution of Cesium Hydroxide in Water Is Exothermic Δ\DeltaΔ Hsoln = -71

The Dissolution of Cesium Hydroxide in Water Is Exothermic $\Delta$ H_soln = -71