Ammonium nitrate 80.04 g/mol) decomposes at high temperatures to form nitrogen, oxygen, and water vapor.Suppose 750 grams decomposes at 350 $\degree$ C and 0.98 atm, generating gases that expand by about 960 L.How much P-V work is done? What is the approximate change in internal energy ( $\Delta$ E ) of the reaction system? (1 L. atm =101.3 J)
NH₄ NO₃ (s) $\rightarrow$ N₂ (g)+ 1/ 2 O₂ (g) + 2H₂ O(g) $\Delta$ H =- 118 kJ/mol

Question

Ammonium nitrate 80.04 g/mol) decomposes at high temperatures to form nitrogen, oxygen, and water vapor.Suppose 750 grams decomposes at 350

\degree

C and 0.98 atm, generating gases that expand by about 960 L.How much P-V work is done? What is the approximate change in internal energy (

\Delta

E ) of the reaction system? (1 L. atm =101.3 J)
NH₄ NO₃ (s)

\rightarrow

N₂ (g)+ 1/ 2 O₂ (g) + 2H₂ O(g)

\Delta

H =- 118 kJ/mol

Quizplus · Accepted Answer

The Answer of Ammonium nitrate 80.04 g/mol) decomposes at high temperatures to form nitrogen, oxygen, and water vapor.Suppose 750 grams decomposes at 350$\degree$C and 0.98 atm, generating gases that expand by about 960 L.How much P-V work is done? What is the approximate change in internal energy ($\Delta$E ) of the reaction system? (1 L. atm =101.3 J) NH₄ NO₃ (s)$\rightarrow$N₂ (g)+ 1/ 2 O₂ (g) + 2H₂ O(g) $\Delta$H =- 118 kJ/mol

Ammonium Nitrate 80 °\degree° C and 098 Atm, Generating Gases That Expand by About 960 L

Ammonium Nitrate 80 $\degree$ C and 098 Atm, Generating Gases That Expand by About 960 L