What force is exerted by a pressure of 2.153 atm on a mercury barometer with an inner diameter of 20.00 mm? Recall that the area of a circle is A = $\pi$r², 1 N = 1 kg m/s², 1 Pa = 1 N/m², and 1 atm = 1.013*10⁵ Pa.

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To find the force exerted by the pressure, first convert the pressure from atm to Pa (since 1 atm = 1.013×10^5 Pa), then calculate the area of the circle using the formula $A = \pi r^2$ (with $r$ being half of the diameter, so 10 mm or 0.01 m), and finally use the formula $F = P \times A$. Given a pressure of 2.153 atm, this converts to $2.153 \times 1.013 \times 10^5$ Pa. The area $A = \pi (0.01)^2$ m^2. The force $F$ calculated with these values results in approximately 68.52 N.

What Force Is Exerted by a Pressure of 2 π\piπ R2, 1 N = 1 Kg M/s2, 1 Pa =

What Force Is Exerted by a Pressure of 2 $\pi$ R², 1 N = 1 Kg M/s², 1 Pa =