A sample of argon gas at 2.90 atm and 35.0 mL is heated from 20.0$\degree$C to 50.0$\degree$C.If the pressure remains constant, what is the final volume of the gas?

Question

Quizplus · Accepted Answer

The final volume of the gas can be calculated using Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin. First, convert the temperatures from Celsius to Kelvin: initial temperature $T_1 = 20.0°C + 273.15 = 293.15 K$, final temperature $T_2 = 50.0°C + 273.15 = 323.15 K$. Using the formula $V_1/T_1 = V_2/T_2$, solve for $V_2$: $V_2 = V_1 \times (T_2/T_1) = 35.0 mL \times (323.15/293.15) ≈ 38.6 mL$.

A Sample of Argon Gas at 2 °\degree° C to 500 °\degree°

A Sample of Argon Gas at 2 $\degree$ C to 500 $\degree$