What is the temperature if 5.00 g of methane (CH₄) in a 100.0 mL container exerts a pressure of 42.0 atm?

Question

Quizplus · Accepted Answer

The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. We can rearrange this equation to solve for T: T = PV/nR. We are given P, V, and n, so we can plug these values into the equation to solve for T.T = (42.0 atm)(0.100 L)/(5.00 g)(0.0821 L atm/mol K) = 1010 KTherefore, the temperature is 1010 K.

What Is the Temperature If 5 °\degree° C) B)(+164 °\degree° C) C)(-272 °\degree°

What Is the Temperature If 5 $\degree$ C)
B)(+164 $\degree$ C)
C)(-272 $\degree$