What is the density of propane gas (CH₃CH₂CH₃, 44.1 g/mol) at 25 $\degree$C and 650 mmHg?

Question

Quizplus · Accepted Answer

The density of a gas can be calculated using the ideal gas law:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.We can rearrange this equation to solve for the density:density = (n/V) * molar masswhere molar mass is the mass of one mole of the gas.We are given the following information:* pressure = 650 mmHg* temperature = 25°C = 298 K* molar mass = 44.1 g/molWe can convert the pressure to atm:650 mmHg * (1 atm / 760 mmHg) = 0.855 atmWe can now calculate the density:density = ((n/V) * molar mass)density = ((P/RT) * molar mass)density = ((0.855 atm / (0.0821 L*atm/(mol*K)) * 298 K) * 44.1 g/mol)density = 1.54 g/LTherefore, the density of propane gas at 25°C and 650 mmHg is 1.54 g/L.

What Is the Density of Propane Gas (CH3CH2CH3, 44 °\degree° C and 650 MmHg? A)1

What Is the Density of Propane Gas (CH₃CH₂CH₃, 44 $\degree$ C and 650 MmHg?
A)1