What is the density of sulfur hexafluoride (SF₆, 146.1 g/mol) in a cylinder at 1.5 atm and 22 $\degree$C?

Question

Quizplus · Accepted Answer

To find the density of sulfur hexafluoride (SF6) under the given conditions, we can use the ideal gas law rearranged to solve for density ($\rho$):$\rho = \frac{PM}{RT}$Where:- $P$ is the pressure (1.5 atm),- $M$ is the molar mass of SF6 (146.1 g/mol),- $R$ is the ideal gas constant (0.0821 L·atm/(K·mol) when using atm for pressure and L for volume),- $T$ is the temperature in Kelvin. To convert 22°C to Kelvin, $T = 22 + 273.15 = 295.15 K$.Plugging in the values:$\rho = \frac{(1.5 \, \text{atm}) \times (146.1 \, \text{g/mol})}{(0.0821 \, \text{L·atm/(K·mol)}) \times (295.15 \, \text{K})}$$\rho \approx 9.1 \, \text{g/L}$Therefore, the density of sulfur hexafluoride under the given conditions is approximately 9.1 g/L.

What Is the Density of Sulfur Hexafluoride (SF6, 146 °\degree° C? A)0

What Is the Density of Sulfur Hexafluoride (SF₆, 146 $\degree$ C?
A)0