A solution is prepared by adding 0.300 mol of glucose, which is not volatile, to 4.50 mol of water.What is the vapor pressure of this solution at 25 $\degree$C given that the vapor pressure of pure water is 23.8 torr?

Question

Quizplus · Accepted Answer

The vapor pressure of the solution can be calculated using Raoult's Law: P_solution = X_solvent * P_pure solvent. The mole fraction of water (solvent) is 4.50 / (4.50 + 0.300) = 0.9375. Thus, P_solution = 0.9375 * 23.8 torr = 22.3 torr.

A Solution Is Prepared by Adding 0 °\degree° C Given That the Vapor Pressure of Pure Water Is

A Solution Is Prepared by Adding 0 $\degree$ C Given That the Vapor Pressure of Pure Water Is