The vapor pressure of an aqueous solution is found to be 24.9 mmHg at 25 $\degree$C.What is the mole fraction of solute in this solution? The vapor pressure of water is 25.756 mmHg at 25 $\degree$C.

Question

Quizplus · Accepted Answer

The mole fraction of the solute in the solution can be calculated using Raoult's law, which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent. The formula to calculate the mole fraction of the solute ($X_{solute}$) is given by $X_{solute} = 1 - \frac{P_{solution}}{P_{solvent}}$, where $P_{solution}$ is the vapor pressure of the solution and $P_{solvent}$ is the vapor pressure of the pure solvent. Substituting the given values, $X_{solute} = 1 - \frac{24.9}{25.756} = 0.033$.

The Vapor Pressure of an Aqueous Solution Is Found to Be