How many grams of potassium nitrate (KNO₃) must be added to 450.0 g of water to produce a 1.30 m solution?

Question

Quizplus · Accepted Answer

To solve this, we use the formula for molality (m), which is moles of solute per kilogram of solvent. Given a 1.30 m solution, we need 1.30 moles of KNO3 per kg of water. Since we have 450.0 g (or 0.45 kg) of water, we need 1.30 mol/kg * 0.45 kg = 0.585 moles of KNO3. The molar mass of KNO3 is approximately 101 g/mol, so the mass of KNO3 needed is 0.585 mol * 101 g/mol = 59.1 g.

How Many Grams of Potassium Nitrate (KNO3) Must Be Added

How Many Grams of Potassium Nitrate (KNO₃) Must Be Added