The enthalpy of vaporization of ammonia at its normal boiling point,-33.34 C, is approximately 23.35 kJ/mol.What is the entropy change in the surroundings when one mole of liquid ammonia vaporizes at -33.34 C in a large room maintained at a temperature of 25.0 C?
A) (-2.40 *102 J/K)
B) (-78.3 J/K)
C) (-19.1 J/K)
D) (+78.3 J/K)
E) (+2.40 * 102 J/K)
Correct Answer:
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