The enthalpy of vaporization for bromine (Br₂) is 184.3 kJ/kg, and its melting point is 59.3$\degree$C.What is the entropy change when 1 mole of bromine vaporizes at 59.3$\degree$C?

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Quizplus · Accepted Answer

The entropy change (ΔS) can be calculated using the formula ΔS = ΔH/T, where ΔH is the enthalpy of vaporization and T is the temperature in Kelvin. First, convert the melting point from Celsius to Kelvin (59.3°C = 332.45 K). Then, convert the enthalpy from kJ/kg to J/mol (184.3 kJ/kg * 159.808 g/mol = 29440 J/mol). Finally, calculate ΔS = 29440 J/mol / 332.45 K = 88.59 J/K.

The Enthalpy of Vaporization for Bromine (Br2) Is 184 °\degree° CWhat Is the Entropy Change When 1 Mole of Bromine

The Enthalpy of Vaporization for Bromine (Br₂) Is 184 $\degree$ CWhat Is the Entropy Change When 1 Mole of Bromine