A second-order reaction (2 A $\rightarrow$ B) with a rate constant of 0.350 M^-1 s^-1 is found to have a half-life of 3.45 s.What was the initial concentration of the reactant, [A] ₀?

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For a second-order reaction, the half-life is given by t₁/₂ = 1 / (k[A]₀). Rearranging for [A]₀ gives [A]₀ = 1 / (k * t₁/₂). Substituting the given values, [A]₀ = 1 / (0.350 M⁻¹s⁻¹ * 3.45 s) = 0.828 M.

A Second-Order Reaction (2 A →\rightarrow→ B) with a Rate Constant of 0

A Second-Order Reaction (2 A $\rightarrow$ B) with a Rate Constant of 0