The rate constant for the first-order decomposition of a particular hydrocarbon is 1.85 *10-6 s-1 at 485 K.If the activation energy is 84.0 kJ/mol, what is the value of the frequency factor at this temperature?
A) 4.85 * 10-4 s-1
B) 1.11*109 s-1
C) 2.21 * 101 s-1
D) 2.06 * 103 s-1
E) 1.81 * 10 -6 s-1
Correct Answer:
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