For an equilibrium reaction with K = 1.2 * 108, the forward rate constant was found to be 3.5*105.What is the value of the reverse rate constant?
A) 3.5 *105
B) 3.4*102
C) 4.2 * 1013
D) 6.0 * 10-
E) 2.9 * 10-3
Correct Answer:
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