The decomposition of NOCl to form NO and Cl₂, 2 NOCl(g) ⇄ 2 NO(g) + CL₂ (g), has a K_p value of 1.6 *10^-5 at some temperature.If the initial partial pressures of NO and Cl₂ in a closed container are 0.80 atm and 0.40 atm, respectively, what is the approximate equilibrium partial pressure of NOCl?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is:K_p = (P_NO)²(P_Cl2) / (P_NOCl)²Substituting the given values into the expression, we get:1.6 x 10^-5 = (0.80 atm)²(0.40 atm) / (P_NOCl)²Solving for P_NOCl, we get:P_NOCl = 0.79 atmTherefore, the approximate equilibrium partial pressure of NOCl is 0.79 atm.

The Decomposition of NOCl to Form NO and Cl2, 2

The Decomposition of NOCl to Form NO and Cl₂, 2