Iodic acid, HIO₃, dissociates in water according to the following reaction.
$\mathrm{HIO}_{3}(a q) \leftrightarrows \mathrm{H}^{+}(a q)+\mathrm{IO}_{3}^{-}(a q) \quad K_{\mathrm{c}}=0.17$ What is the concentration of H⁺ in a 0.0100 M solution of HIO₃?

Question

Iodic acid, HIO₃, dissociates in water according to the following reaction.

\mathrm{HIO}_{3}(a q) \leftrightarrows \mathrm{H}^{+}(a q)+\mathrm{IO}_{3}^{-}(a q) \quad K_{\mathrm{c}}=0.17

What is the concentration of H⁺ in a 0.0100 M solution of HIO₃?

Quizplus · Accepted Answer

The Answer of Iodic acid, HIO₃, dissociates in water according to the following reaction. $ \mathrm{HIO}_{3}(a q) \leftrightarrows \mathrm{H}^{+}(a q)+\mathrm{IO}_{3}^{-}(a q) \quad K_{\mathrm{c}}=0.17 $ What is the concentration of H⁺ in a 0.0100 M solution of HIO₃?

Iodic Acid, HIO3, Dissociates in Water According to the Following HIO3(aq)⇆H+(aq)+IO3−(aq)Kc=0.17 \mathrm{HIO}_{3}(a q) \leftrightarrows \mathrm{H}^{+}(a q)+\mathrm{IO}_{3}^{-}(a q) \quad K_{\mathrm{c}}=0.17 HIO3​(aq)⇆H+(aq)+IO3−​(aq)Kc​=0.17

Iodic Acid, HIO₃, Dissociates in Water According to the Following $\mathrm{HIO}_{3}(a q) \leftrightarrows \mathrm{H}^{+}(a q)+\mathrm{IO}_{3}^{-}(a q) \quad K_{\mathrm{c}}=0.17$