What is the percent dissociation of 0.40 M butyric acid (HC₄H₇O₂)? (The K_a value for butyric acid is 1.48 * 10^-5.)

Name: What is the percent dissociation of 0.40 M butyric acid (HC 4 H 7 O 2 )? (The K a value for butyric acid is 1.48 * 10 -5 .)
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Percent dissociation is calculated using the formula: % dissociation = ([H⁺]/[HA]₀) × 100. For butyric acid, [H⁺] = √(Kₐ × [HA]₀) = √(1.48 × 10⁻⁵ × 0.40) = 0.00244 M. Thus, % dissociation = (0.00244/0.40) × 100 = 0.61%.

What Is the Percent Dissociation of 0