Iron (Fe) has a density of 7.87 g/cm³ and crystallizes in a body-centered cubic structure.What is the atomic radius of iron?

Question

Quizplus · Accepted Answer

The atomic radius of iron in a body-centered cubic (BCC) structure can be calculated using the formula for the volume of the unit cell and the density. In a BCC structure, the diagonal of the cube (4r) is equal to the square root of 3 times the edge length (a), where r is the atomic radius. Given the density and knowing that there are 2 atoms per BCC unit cell, we can calculate the atomic radius. The correct calculation leads to an atomic radius of approximately 124 pm.

Iron (Fe) Has a Density of 7