A person's body generates about 0.2 µCi of radioactivity.Determine the total radioactivity in decays per second emitted by 300 students in a lecture hall.(1 Ci = 3.7 *1010 Bq and 1 Bq = 1 decay/s)

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Quizplus · Accepted Answer

First, convert the radioactivity per person to decays per second: 0.2 µCi/person = 0.2 × 10^-6 Ci/person. Since 1 Ci = 3.7 × 10^10 Bq and 1 Bq = 1 decay/s, each person emits 0.2 × 10^-6 × 3.7 × 10^10 = 7.4 × 10^4 decays/s. For 300 students, the total radioactivity is 300 × 7.4 × 10^4 = 2.22 × 10^7 decays/s, which is approximately 2 × 10^7 decays/s.

A Person's Body Generates About 0