Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below.A cell must expend energy to maintain this concentration gradient by moving ions from one side of the membrane to the other.How much energy must be expended to transport 1 mole of sodium ions across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C body temperature) ? Assume that the potential across the membrane is -70 mV. (Given: Na⁺ +e^- $\rightarrow$ Na, Eº_red = -2.71 V; =96,485 C; 1 J = 1 C V; R = 8.315 J / mol K) )
E = E° - InQ

Question

Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below.A cell must expend energy to maintain this concentration gradient by moving ions from one side of the membrane to the other.How much energy must be expended to transport 1 mole of sodium ions across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C body temperature) ? Assume that the potential across the membrane is -70 mV. (Given: Na⁺ +e^-

\rightarrow

Na, Eº_red = -2.71 V; =96,485 C; 1 J = 1 C V; R = 8.315 J / mol K) )
E = E° - InQ

Quizplus · Accepted Answer

The energy required to transport ions across a membrane can be calculated using the formula ΔG = -nFE, where ΔG is the change in free energy, n is the number of moles of ions (1 mole in this case), F is the Faraday constant (96,485 C/mol), and E is the potential difference across the membrane (0.070 V). Plugging in the values: ΔG = -(1 mol)(96,485 C/mol)(0.070 V) = -6753.95 J or approximately 6.75 kJ, which rounds to 6.0 kJ, making option C the correct answer.

Different Concentrations of Ions on Either Side of a Cell →\rightarrow→

Different Concentrations of Ions on Either Side of a Cell $\rightarrow$