Determine the equation of the plane which contains the points (1, 2, -8)and (-2, 1, -8)and is perpendicular to the plane $x + 3 y - 8 z = 2$ .

Name: Determine the equation of the plane which contains the points (1, 2, -8)and (-2, 1, -8)and is perpendicular to the plane $x + 3 y - 8 z = 2$ .
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The Answer of Determine the equation of the plane which contains the points (1, 2, -8)and (-2, 1, -8)and is perpendicular to the plane $x + 3 y - 8 z = 2$ .

Determine the Equation of the Plane Which Contains the Points x+3y−8z=2x + 3 y - 8 z = 2x+3y−8z=2

Determine the Equation of the Plane Which Contains the Points $x + 3 y - 8 z = 2$