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A Spherical Raindrop Evaporates at a Rate Proportional to Its V=43πr3V=\frac{4}{3} \pi r^{3}

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A spherical raindrop evaporates at a rate proportional to its surface area.Let V = volume of the raindrop and S = surface area.For a sphere, V=43πr3V=\frac{4}{3} \pi r^{3} and S=4πr2S=4 \pi r^{2} .If it takes 6 minutes for a spherical raindrop to evaporate to 18\frac{1}{8} of its original volume, how many minutes will it take to completely evaporate?

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