Suppose the equations $\frac{d y}{d t}=4 y-x y$ and $\frac{d x}{d t}=x-x y$ describe the rates of growth of two interacting species, where x is the number of species A, measured in thousands, and y is the number of species B, measured in thousands.Assuming that the initial conditions are 1000 of species A and 2000 of species B.What is the long run behavior of Species A?
A)It dies out.
B)It grows exponentially.
C)It reaches an equilibrium.

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The Answer of Suppose the equations $\frac{d y}{d t}=4 y-x y$ and $\frac{d x}{d t}=x-x y$ describe the rates of growth of two interacting species, where x is the number of species A, measured in thousands, and y is the number of species B, measured in thousands.Assuming that the initial conditions are 1000 of species A and 2000 of species B.What is the long run behavior of Species A?
A)It dies out.
B)It grows exponentially.
C)It reaches an equilibrium.

Suppose the Equations dydt=4y−xy\frac{d y}{d t}=4 y-x ydtdy​=4y−xy And dxdt=x−xy\frac{d x}{d t}=x-x ydtdx​=x−xy

Suppose the Equations $\frac{d y}{d t}=4 y-x y$ And $\frac{d x}{d t}=x-x y$