$\int \sin (\sqrt{y}) d y=\sin \sqrt{y}-\sqrt{y} \cos \sqrt{y}+C$ .

Name: $\int \sin (\sqrt{y}) d y=\sin \sqrt{y}-\sqrt{y} \cos \sqrt{y}+C$ .
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Question

Quizplus · Accepted Answer

The integral $\int \sin (\sqrt{y}) d y$ cannot be directly expressed in terms of elementary functions involving just $\sin \sqrt{y}$ and $\cos \sqrt{y}$ without an integration process involving substitution or other methods, and the provided expression is not a correct result of this integral.

∫sin⁡(y)dy=sin⁡y−ycos⁡y+C\int \sin (\sqrt{y}) d y=\sin \sqrt{y}-\sqrt{y} \cos \sqrt{y}+C∫sin(y​)dy=siny​−y​cosy​+C

$\int \sin (\sqrt{y}) d y=\sin \sqrt{y}-\sqrt{y} \cos \sqrt{y}+C$