A man plans to propose to a woman in romantic fashion by taking her up in an air balloon.Unfortunately, he pulls the diamond ring from his pocket and drops it over the side of the balloon's basket.The ring's position above the earth t seconds after it falls is given by the function $s(t)=-16 t^{2}+1225$
feet.How fast is the ring falling 3 seconds after he drops it?

Question

A man plans to propose to a woman in romantic fashion by taking her up in an air balloon.Unfortunately, he pulls the diamond ring from his pocket and drops it over the side of the balloon's basket.The ring's position above the earth t seconds after it falls is given by the function $s(t)=-16 t^{2}+1225$
 feet.How fast is the ring falling 3 seconds after he drops it?

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The Answer of A man plans to propose to a woman in romantic fashion by taking her up in an air balloon.Unfortunately, he pulls the diamond ring from his pocket and drops it over the side of the balloon's basket.The ring's position above the earth t seconds after it falls is given by the function $s(t)=-16 t^{2}+1225$
 feet.How fast is the ring falling 3 seconds after he drops it?

A Man Plans to Propose to a Woman in Romantic s(t)=−16t2+1225s(t)=-16 t^{2}+1225s(t)=−16t2+1225

A Man Plans to Propose to a Woman in Romantic $s(t)=-16 t^{2}+1225$