The derivative of $6 ^ { e } - \frac { 6 } { x } + \sqrt { 1 - x }$ is $\frac { 6 } { x ^ { 2 } } + \frac { 1 } { 2 \sqrt { 1 - x } }$ .

Question

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The derivative of $6^e - \frac{6}{x} + \sqrt{1 - x}$ is incorrect as stated because the derivative of a constant raised to the power of $e$ (like $6^e$) is 0, not included in the provided derivative. The correct derivative should be $0 - \frac{6}{x^2} - \frac{1}{2\sqrt{1-x}}$, taking into account the derivative of each term separately.

The Derivative Of 6e−6x+1−x6 ^ { e } - \frac { 6 } { x } + \sqrt { 1 - x }6e−x6​+1−x​

The Derivative Of $6 ^ { e } - \frac { 6 } { x } + \sqrt { 1 - x }$