A golf ball thrown directly upwards from the surface of the moon with an initial velocity of 14.00 meters per second and will attain a height of $s(t) =-0.8 t^{2}+14.00 t$
meters in t seconds.What is the acceleration of the golf ball at time t?

Question

A golf ball thrown directly upwards from the surface of the moon with an initial velocity of 14.00 meters per second and will attain a height of

s(t) =-0.8 t^{2}+14.00 t

meters in t seconds.What is the acceleration of the golf ball at time t?

Quizplus · Accepted Answer

The acceleration of the golf ball is the second derivative of the position function $s(t) = -0.8t^2 + 14.00t$. Differentiating twice, we get $s''(t) = -1.6$, which is constant and represents the acceleration.

A Golf Ball Thrown Directly Upwards from the Surface of the Moon