Lee shipped three packages to New York. If the packages weighed $27 \frac { 1 } { 6 }$ , $40 \frac { 1 } { 3 }$ , and $10 \frac { 5 } { 6 }$ pounds, what was the total weight?

Question

Quizplus · Accepted Answer

To find the total weight, add the weights of the three packages: $27 \frac { 1 } { 6 } + 40 \frac { 1 } { 3 } + 10 \frac { 5 } { 6 }$. Convert the fractions to have a common denominator of 6, resulting in $27 \frac { 1 } { 6 } + 40 \frac { 2 } { 6 } + 10 \frac { 5 } { 6 }$. Adding these together gives $77 \frac { 8 } { 6 }$, which simplifies to $78 \frac { 1 } { 3 }$ pounds.

Lee Shipped Three Packages to New York 271627 \frac { 1 } { 6 }2761​

Lee Shipped Three Packages to New York $27 \frac { 1 } { 6 }$