A motorcycle with a mass of 100 kilograms, slowly rolls over the edge of a cliff and falls for three seconds before it reaches the bottom of a gully. Its momentum ( in units of kilogram meters per second) just before it hit bottom and became burned rubber and scrap metal was

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Quizplus · Accepted Answer

The motorcycle's momentum just before hitting the bottom can be calculated using the formula for momentum, $p = mv$, where $m$ is the mass and $v$ is the velocity. To find the velocity, we use the formula for free fall, $v = gt$, where $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$) and $t$ is the time. Substituting $g = 9.8 \, \text{m/s}^2$ and $t = 3 \, \text{s}$, we get $v = 9.8 \times 3 = 29.4 \, \text{m/s}$. The mass of the motorcycle is $100 \, \text{kg}$, so the momentum is $100 \times 29.4 = 2940 \, \text{kg m/s}$, which rounds to $3000 \, \text{kg m/s}$, making option C correct.

A Motorcycle with a Mass of 100 Kilograms, Slowly Rolls