A 2000-kg car experiences a braking force of 10,000 N and skids to a stop in 6 seconds. The speed of the car just before the brakes were applied was

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Quizplus · Accepted Answer

The braking force causes a deceleration, which can be calculated using Newton's second law: $ a = \frac{F}{m} = \frac{10000 \, \text{N}}{2000 \, \text{kg}} = 5 \, \text{m/s}^2 $. The initial speed can be found using the equation $ v = u + at $, where $ v = 0 $ (final speed), $ a = -5 \, \text{m/s}^2 $ (deceleration), and $ t = 6 \, \text{s} $. Solving for $ u $ gives $ u = v - at = 0 + 5 \times 6 = 30 \, \text{m/s} $.

A 2000-Kg Car Experiences a Braking Force of 10,000 N