A 10-kilogram block with an initial velocity of 10 m/s slides 10 meters across a horizontal surface and comes to rest. It takes the block 2 seconds to stop. The stopping force acting on the block is
About
A) 25 N.
B) 10 N.
C) 50 N.
D) 5 N.
E) none of these

Question

Quizplus · Accepted Answer

The stopping force can be calculated using the formula F = ma, where m is mass and a is acceleration. First, find the acceleration using the formula a = (final velocity - initial velocity) / time = (0 - 10 m/s) / 2 s = -5 m/s². Then, F = 10 kg * (-5 m/s²) = -50 N. The magnitude of the force is 50 N.

A 10-Kilogram Block with an Initial Velocity of 10 M/s