An object, at rest near the surface of a distant planet, starts to fall freely . If the acceleration there is twice that of the earth, its speed one second later would be
A) 40 m/s.
B) 10 m/s.
C) 20 m/s.
D) 30 m/s.

Question

Quizplus · Accepted Answer

The acceleration due to gravity on Earth is approximately 9.8 m/s^2. If the acceleration on the distant planet is twice that of Earth, it would be 2 * 9.8 m/s^2 = 19.6 m/s^2. The speed of an object in free fall after one second can be calculated using the formula v = at, where 'a' is the acceleration and 't' is the time. Substituting the given values, v = 19.6 m/s^2 * 1 s = 19.6 m/s, which is approximately 20 m/s.

An Object, at Rest near the Surface of a Distant